## firestARTer wrote:

Yep, it actualy decreases the need of the full resistor value. You can calculate this by some simple electronics calculations:

T = R*C

T = 470K * 1000pF (the capacity is taken from the original datasheet)

T = 0,47m

Then you use the formula to get the new capacity depending on your resistor: (lets take 200k for example)

C = T / R

C = 0,47m / 200k

C = 2,35 nF ( but they are not possible to get, so 100K and 4,7nF are just fine, or you would have to use 2 x 4,7nF and put them in a row )

Thats for your education!!

I tryed to solder 4,7nf and 100k pots, but the pots are not really 100k (92/95k) so I need to calculate the good value for the capacitor to make the pots more accurate.

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